5a^2=-14a

Solution for 5a^2=-14a equation:

5a^2=-14a

We move all terms to the left:

5a^2-(-14a)=0

We get rid of parentheses

5a^2+14a=0

a = 5; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·5·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*5}=\frac{-28}{10}
=-2+4/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*5}=\frac{0}{10}
=0
$